Swinging choke with bleeder resistor







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EDN is a leading source for reliable electronics design ideas, articles, how to articles and teardowns. Read coveruptattoos.info for the latest information on analog design, automotive design, communications and networking design, consumer electronics design, integrated circuit design, LED design, medical electronics design, electronics power management design, sensor design, electronic systems design. But it does need to 'swing' enough that it will go into resonance with the tuning-capacitor at the desired load, typically when the power supply is only loaded by the bleeder resistor. Then, when current goes up with RF power, the resonant choke goes out of resonance and becomes just a choke input filter.

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Now the choke is a henry swinging choke. So to get the minimum current for the bleeder resistor to have the 20 Henry portion we take / 20mA = 20 Henrys or 20H x 20mA = V. So for 20 mA at Volts, our bleeder resistor would be / = 20K ohms. If your HV power supply doesn't include a bleeder resistor, then you should add one right away! My amp, with a 3KV supply, has a K Ohm, Watt (maybe it's bigger?) bleeder.

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swinging choke. Each cap has a bleeder across it, as I recall, rather than a single bleeder. If the Warrior uses the same style choke input filter, the choke could be bad. Mine was missing - in fact the previous owner had messed with it and substituted something different, which he did not bolt down. I bought the.

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The bleeder resistor can be included in the calculation of load resistance if desired; the effect that it will have on the filtering depends on the curvature of the "C" curve being used. The answer obtained is the percent ripple, which is defined as the r.m.s. value of the output ripple voltage, times , divided by the d.c. voltage.

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First point is why a resonant filter? The answer is that a choke input needs an inductance of a critical minimum value. Because of saturation in the core of a choke with no air gaps, the choke inductance decreases with current: this is a swinging choke.

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Simply go find yourself a 50K ohm, or watt wirewound bleeder resistor and call it quits. That will only involve 45 watts being dissapated continously with a draw of 30mA. That works out to be only 10% of the supply's capabilities, which also coincides with the magic 10% that was used for many years.

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I've heard of swinging choke, but not sure on principle how they work. Is there an electronic way of varying the gap/ preventing saturation. I'm thinking if so, one could build a power supply with LC filtering to work through an extended range low to high voltage.

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the smoothing choke (L) was simply relocated in the circuit and used as the audio choke while the bleeder resistor and output filter capacitor were reconnected in the circuit just after the swinging choke. The arrange- ment of Fig. 2 permits the class C am- plifier plate current to be fed through the modulation choke in contrast to.


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Description: This resistor is traditionally called a "bleeder". Since your filter is not choke-input, it cannot have a "bleeder" in that sense. However, the term can also be used nowadays to describe any resistor connected across the filter, regardless of the filter type or the load. Bleeder resistors, too, are a relic of the valve era, and were used largely for safety reasons. On low voltage supplies, they're not necessary. I haven't used a bleeder resistor or a smoothing choke in a power supply design in more than fifty years. sure against resonance effects. With a swinging choke, the minimum rated inductance Of the choke should be used. RATINGS OF FILTER COMPONENTS In a power supply using a choke-input filter and properly-designed choke and bleeder resistor, the no-load voltage across the filter capacitors will be about nine-tenths of the a-c. r.m.s. volt- age.
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